Type Challenges Judge

Append Argument

提出詳細

type AppendArgument<Fn, A> = Fn extends (...args: infer Args) => infer Ret ? (...args: [...Args, A]) => Ret : never
提出日時2023-09-09 03:23:27
問題Append Argument
ユーザーsnaka
ステータスAccepted
テストケース
import type { Equal, Expect } from '@type-challenges/utils' type Case1 = AppendArgument<(a: number, b: string) => number, boolean> type Result1 = (a: number, b: string, x: boolean) => number type Case2 = AppendArgument<() => void, undefined> type Result2 = (x: undefined) => void type cases = [ Expect<Equal<Case1, Result1>>, Expect<Equal<Case2, Result2>>, ]